What is the circumference x^2+y^2-10x+12y-24=0 ?

The circumference x^2+y^2-10x+12y-24=0 is C=2sqrt(85)pi

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circumference x^2+y^2-10x+12y-24=0

circumference

x^{2} + y^{2} - 10 x + 12 y - 24 = 0

C = 285 π

Solution steps

C = 2 π r

Find the radius

Radius given

x^{2} + y^{2} - 10 x + 12 y - 24 = 0 : r = 85

C = 285 π

x^{2} + y^{2} - 6 x + 2 y + 6 = 0

x^{2} + y^{2} - 8 x + 6 y - 24 = 0

2 x^{2} + 2 y^{2} + x + y = 0

5 x^{2} + 5 y^{2} - 30 y - 5 = 0

x^{2} + y^{2} + 5 y = 12

What is the circumference x^2+y^2-10x+12y-24=0 ?
The circumference x^2+y^2-10x+12y-24=0 is C=2sqrt(85)pi