What is the circumference x^2+y^2-8x+6y-24=0 ?

The circumference x^2+y^2-8x+6y-24=0 is C=14pi

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circumference x^2+y^2-8x+6y-24=0

circumference

x^{2} + y^{2} - 8 x + 6 y - 24 = 0

C = 14 π

Solution steps

C = 2 π r

Find the radius

Radius given

x^{2} + y^{2} - 8 x + 6 y - 24 = 0 : r = 7

C = 2 π 7

Refine

C = 14 π

2 x^{2} + 2 y^{2} + x + y = 0

5 x^{2} + 5 y^{2} - 30 y - 5 = 0

x^{2} + y^{2} + 5 y = 12

(x - 2)^{2} + (y - 3)^{2} = 36

x^{2} + y^{2} - 6 x + 2 y - 6 = 0

What is the circumference x^2+y^2-8x+6y-24=0 ?
The circumference x^2+y^2-8x+6y-24=0 is C=14pi