What is the radius 4x^2+4y^2-20x+40y=-5 ?

The radius 4x^2+4y^2-20x+40y=-5 is r=sqrt(30)

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radius 4x^2+4y^2-20x+40y=-5

radius

4 x^{2} + 4 y^{2} - 20 x + 40 y = - 5

r = 30

Solution steps

4 x^{2} + 4 y^{2} - 20 x + 40 y = - 5

Rewrite

4 x^{2} + 4 y^{2} - 20 x + 40 y = - 5

in the form of the standard circle equation

(x - \frac{5}{2})^{2} + (y - (- 5))^{2} = (30)^{2}

Therefore the circle properties are:

(a, b) = (\frac{5}{2}, - 5), r = 30

And the radius is:

r = 30

2 x^{2} + 2 y^{2} + 6 x - 8 y + 12 = 0

16 x^{2} + 16 y^{2} - 8 y - 15 = 0

x^{2} + y^{2} + 4 x + 6 y = 23

x^{2} + y^{2} - 10 x + 2 y = 0

(x + 4)^{2} + y^{2} = 4

What is the radius 4x^2+4y^2-20x+40y=-5 ?
The radius 4x^2+4y^2-20x+40y=-5 is r=sqrt(30)