What is the radius (x+4)^2+y^2=4 ?

The radius (x+4)^2+y^2=4 is r=2

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radius (x+4)^2+y^2=4

radius

(x + 4)^{2} + y^{2} = 4

r = 2

Solution steps

(x + 4)^{2} + y^{2} = 4

Rewrite

(x + 4)^{2} + y^{2} = 4

in the form of the standard circle equation

(x - (- 4))^{2} + (y - 0)^{2} = 2^{2}

Therefore the circle properties are:

(a, b) = (- 4, 0), r = 2

And the radius is:

r = 2

(x + 1)^{2} + (y + 2)^{2} = 36

+ x^{2} + y^{2} - 18 x - 14 y + 124 = 0

(x - 5)^{2} + (y - 1)^{2} = 49

(x + 2)^{2} + (y + 3)^{2} = 9

(x + 12)^{2} + (y - 4)^{2} - 30 = 0