What is the radius 16x^2+16y^2-8y-15=0 ?

The radius 16x^2+16y^2-8y-15=0 is r=1

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radius 16x^2+16y^2-8y-15=0

radius

16 x^{2} + 16 y^{2} - 8 y - 15 = 0

r = 1

Solution steps

16 x^{2} + 16 y^{2} - 8 y - 15 = 0

Rewrite

16 x^{2} + 16 y^{2} - 8 y - 15 = 0

in the form of the standard circle equation

(x - 0)^{2} + (y - \frac{1}{4})^{2} = 1^{2}

Therefore the circle properties are:

(a, b) = (0, \frac{1}{4}), r = 1

And the radius is:

r = 1

x^{2} + y^{2} + 4 x + 6 y = 23

x^{2} + y^{2} - 10 x + 2 y = 0

(x + 4)^{2} + y^{2} = 4

(x + 1)^{2} + (y + 2)^{2} = 36

+ x^{2} + y^{2} - 18 x - 14 y + 124 = 0