What is the radius x^2+y^2+4x+6y=23 ?

The radius x^2+y^2+4x+6y=23 is r=6

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radius x^2+y^2+4x+6y=23

radius

x^{2} + y^{2} + 4 x + 6 y = 23

r = 6

Solution steps

x^{2} + y^{2} + 4 x + 6 y = 23

Rewrite

x^{2} + y^{2} + 4 x + 6 y = 23

in the form of the standard circle equation

(x - (- 2))^{2} + (y - (- 3))^{2} = 6^{2}

Therefore the circle properties are:

(a, b) = (- 2, - 3), r = 6

And the radius is:

r = 6

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(x - 5)^{2} + (y - 1)^{2} = 49