What is the radius x^2+y^2-8x-12y+43=0 ?

The radius x^2+y^2-8x-12y+43=0 is r=3

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radius x^2+y^2-8x-12y+43=0

radius

x^{2} + y^{2} - 8 x - 12 y + 43 = 0

r = 3

Solution steps

x^{2} + y^{2} - 8 x - 12 y + 43 = 0

Rewrite

x^{2} + y^{2} - 8 x - 12 y + 43 = 0

in the form of the standard circle equation

(x - 4)^{2} + (y - 6)^{2} = 3^{2}

Therefore the circle properties are:

(a, b) = (4, 6), r = 3

And the radius is:

r = 3

x^{2} - 2 x + y^{2} + 4 y = 11

x^{2} + y^{2} - 9 x + 4 y - 181 = 0

x^{2} + y^{2} - 32 x - 60 y + 1122 = 0

x^{2} + y^{2} < 9

36 x^{2} + 36 y^{2} - 24 x + 36 y - 245 = 0