What is the radius (x-2)^2+y^2=25 ?

The radius (x-2)^2+y^2=25 is r=5

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radius (x-2)^2+y^2=25

radius

(x - 2)^{2} + y^{2} = 25

r = 5

Solution steps

(x - 2)^{2} + y^{2} = 25

Rewrite

(x - 2)^{2} + y^{2} = 25

in the form of the standard circle equation

(x - 2)^{2} + (y - 0)^{2} = 5^{2}

Therefore the circle properties are:

(a, b) = (2, 0), r = 5

And the radius is:

r = 5

x^{2} + y^{2} - 4 x = 5

x^{2} + y^{2} + 2 x - 10 y - 10 = 0

(x + 5)^{2} + (y - 7)^{2} = 289

x^{2} + y^{2} + 2 x - 6 y = 0

x^{2} + y^{2} - 2 x - 4 y + 1 = 0