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Popular >

radius x^2+y^2-4x=5

Solution

radius

x^{2} + y^{2} - 4 x = 5

Solution

r = 3

Solution steps

x^{2} + y^{2} - 4 x = 5

Rewrite

x^{2} + y^{2} - 4 x = 5

in the form of the standard circle equation

(x - 2)^{2} + (y - 0)^{2} = 3^{2}

Therefore the circle properties are:

(a, b) = (2, 0), r = 3

And the radius is:

r = 3

Popular Examples

radius x^2+y^2+2x-10y-10=0 radius

x^{2} + y^{2} + 2 x - 10 y - 10 = 0

radius (x+5)^2+(y-7)^2=289 radius

(x + 5)^{2} + (y - 7)^{2} = 289

radius x^2+y^2+2x-6y=0 radius

x^{2} + y^{2} + 2 x - 6 y = 0

radius x^2+y^2-2x-4y+1=0 radius

x^{2} + y^{2} - 2 x - 4 y + 1 = 0

radius x^2+y^2+2x-4y=5.7 radius

x^{2} + y^{2} + 2 x - 4 y = 5.7

Frequently Asked Questions (FAQ)

What is the radius x^2+y^2-4x=5 ?
The radius x^2+y^2-4x=5 is r=3