What is the radius x^2+y^2-9x+4y-181=0 ?

The radius x^2+y^2-9x+4y-181=0 is r=(sqrt(821))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

radius x^2+y^2-9x+4y-181=0

radius

x^{2} + y^{2} - 9 x + 4 y - 181 = 0

r = \frac{821}{2}

Solution steps

x^{2} + y^{2} - 9 x + 4 y - 181 = 0

Rewrite

x^{2} + y^{2} - 9 x + 4 y - 181 = 0

in the form of the standard circle equation

(x - \frac{9}{2})^{2} + (y - (- 2))^{2} = (\frac{821}{2})^{2}

Therefore the circle properties are:

(a, b) = (\frac{9}{2}, - 2), r = \frac{821}{2}

And the radius is:

r = \frac{821}{2}

x^{2} + y^{2} - 32 x - 60 y + 1122 = 0

x^{2} + y^{2} < 9

36 x^{2} + 36 y^{2} - 24 x + 36 y - 245 = 0

x^{2} + y^{2} + 10 x - 18 y + 70 = 0

(x - 2)^{2} + y^{2} = 25

What is the radius x^2+y^2-9x+4y-181=0 ?
The radius x^2+y^2-9x+4y-181=0 is r=(sqrt(821))/2