What is the radius x^2-10x+y^2+6y-1=0 ?

The radius x^2-10x+y^2+6y-1=0 is r=sqrt(35)

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radius x^2-10x+y^2+6y-1=0

radius

x^{2} - 10 x + y^{2} + 6 y - 1 = 0

r = 35

Solution steps

x^{2} - 10 x + y^{2} + 6 y - 1 = 0

Rewrite

x^{2} - 10 x + y^{2} + 6 y - 1 = 0

in the form of the standard circle equation

(x - 5)^{2} + (y - (- 3))^{2} = (35)^{2}

Therefore the circle properties are:

(a, b) = (5, - 3), r = 35

And the radius is:

r = 35

5 x^{2} + 5 y^{2} - 36 x + 98 y - 1 = 0

x^{2} + y^{2} + 14 x - 16 y + 64 = 0

9 x^{2} + 9 y^{2} + 18 x - 18 y + 14 = 0

- 20 - x^{2} = - 16 x - 20 y + y^{2}

x^{2} + y^{2} - 8 x + 6 y + 16 = 0

What is the radius x^2-10x+y^2+6y-1=0 ?
The radius x^2-10x+y^2+6y-1=0 is r=sqrt(35)