What is the radius x^2+y^2-8x+6y+16=0 ?

The radius x^2+y^2-8x+6y+16=0 is r=3

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radius x^2+y^2-8x+6y+16=0

radius

x^{2} + y^{2} - 8 x + 6 y + 16 = 0

r = 3

Solution steps

x^{2} + y^{2} - 8 x + 6 y + 16 = 0

Rewrite

x^{2} + y^{2} - 8 x + 6 y + 16 = 0

in the form of the standard circle equation

(x - 4)^{2} + (y - (- 3))^{2} = 3^{2}

Therefore the circle properties are:

(a, b) = (4, - 3), r = 3

And the radius is:

r = 3

x^{2} + (y - 1)^{2} = 36

x^{2} + y^{2} + 2 x + 6 y + 2 = 0

x^{2} + y^{2} + 14 x - 2 y = 225

x^{2} + y^{2} - 2 x - 4 y - 31 = 0

x^{2} + y^{2} + 4 x - 6 y + 12 = 0