What is the radius x^2+y^2+14x-16y+64=0 ?

The radius x^2+y^2+14x-16y+64=0 is r=7

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radius x^2+y^2+14x-16y+64=0

radius

x^{2} + y^{2} + 14 x - 16 y + 64 = 0

r = 7

Solution steps

x^{2} + y^{2} + 14 x - 16 y + 64 = 0

Rewrite

x^{2} + y^{2} + 14 x - 16 y + 64 = 0

in the form of the standard circle equation

(x - (- 7))^{2} + (y - 8)^{2} = 7^{2}

Therefore the circle properties are:

(a, b) = (- 7, 8), r = 7

And the radius is:

r = 7

9 x^{2} + 9 y^{2} + 18 x - 18 y + 14 = 0

- 20 - x^{2} = - 16 x - 20 y + y^{2}

x^{2} + y^{2} - 8 x + 6 y + 16 = 0

x^{2} + (y - 1)^{2} = 36

x^{2} + y^{2} + 2 x + 6 y + 2 = 0

What is the radius x^2+y^2+14x-16y+64=0 ?
The radius x^2+y^2+14x-16y+64=0 is r=7