What is the radius 9x^2+9y^2+18x-18y+14=0 ?

The radius 9x^2+9y^2+18x-18y+14=0 is r= 2/3

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radius 9x^2+9y^2+18x-18y+14=0

radius

9 x^{2} + 9 y^{2} + 18 x - 18 y + 14 = 0

r = \frac{2}{3}

Solution steps

9 x^{2} + 9 y^{2} + 18 x - 18 y + 14 = 0

Rewrite

9 x^{2} + 9 y^{2} + 18 x - 18 y + 14 = 0

in the form of the standard circle equation

(x - (- 1))^{2} + (y - 1)^{2} = (\frac{2}{3})^{2}

Therefore the circle properties are:

(a, b) = (- 1, 1), r = \frac{2}{3}

And the radius is:

r = \frac{2}{3}

- 20 - x^{2} = - 16 x - 20 y + y^{2}

x^{2} + y^{2} - 8 x + 6 y + 16 = 0

x^{2} + (y - 1)^{2} = 36

x^{2} + y^{2} + 2 x + 6 y + 2 = 0

x^{2} + y^{2} + 14 x - 2 y = 225

What is the radius 9x^2+9y^2+18x-18y+14=0 ?
The radius 9x^2+9y^2+18x-18y+14=0 is r= 2/3