What is the radius x^2+(y-3)^2=2.6 ?

The radius x^2+(y-3)^2=2.6 is r=1.61245…

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radius x^2+(y-3)^2=2.6

radius

x^{2} + (y - 3)^{2} = 2.6

r = 1.61245 \dots

Solution steps

x^{2} + (y - 3)^{2} = 2.6

Rewrite

x^{2} + (y - 3)^{2} = 2.6

in the form of the standard circle equation

(x - 0)^{2} + (y - 3)^{2} = 1.61245 \dots^{2}

Therefore the circle properties are:

(a, b) = (0, 3), r = 1.61245 \dots

And the radius is:

r = 1.61245 \dots

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