What is the radius x^2+y^2+6x-10y+18=0 ?

The radius x^2+y^2+6x-10y+18=0 is r=4

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radius x^2+y^2+6x-10y+18=0

radius

x^{2} + y^{2} + 6 x - 10 y + 18 = 0

r = 4

Solution steps

x^{2} + y^{2} + 6 x - 10 y + 18 = 0

Rewrite

x^{2} + y^{2} + 6 x - 10 y + 18 = 0

in the form of the standard circle equation

(x - (- 3))^{2} + (y - 5)^{2} = 4^{2}

Therefore the circle properties are:

(a, b) = (- 3, 5), r = 4

And the radius is:

r = 4

(x - 1)^{2} + (y - 2)^{2} = 36

x^{2} + y^{2} - 6 x + 8 y = 144

x^{2} - 10 x + y^{2} + 6 y - 1 = 0

5 x^{2} + 5 y^{2} - 36 x + 98 y - 1 = 0

x^{2} + y^{2} + 14 x - 16 y + 64 = 0