What is the radius 9x^2+9y^2+42x+84y+65=0 ?

The radius 9x^2+9y^2+42x+84y+65=0 is r=2sqrt(5)

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radius 9x^2+9y^2+42x+84y+65=0

radius

9 x^{2} + 9 y^{2} + 42 x + 84 y + 65 = 0

r = 25

Solution steps

9 x^{2} + 9 y^{2} + 42 x + 84 y + 65 = 0

Rewrite

9 x^{2} + 9 y^{2} + 42 x + 84 y + 65 = 0

in the form of the standard circle equation

(x - (- \frac{7}{3}))^{2} + (y - (- \frac{14}{3}))^{2} = (25)^{2}

Therefore the circle properties are:

(a, b) = (- \frac{7}{3}, - \frac{14}{3}), r = 25

And the radius is:

r = 25

x^{2} + y^{2} + 6 x - 10 y + 18 = 0

(x - 1)^{2} + (y - 2)^{2} = 36

x^{2} + y^{2} - 6 x + 8 y = 144

x^{2} - 10 x + y^{2} + 6 y - 1 = 0

5 x^{2} + 5 y^{2} - 36 x + 98 y - 1 = 0

What is the radius 9x^2+9y^2+42x+84y+65=0 ?
The radius 9x^2+9y^2+42x+84y+65=0 is r=2sqrt(5)