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Popular >

integral from-1 to 1 of 4-4x^2

Solution

\int_{- 1}^{1} 4 - 4 x^{2} d x

Solution

\frac{16}{3}

+1

Solution steps

\int_{- 1}^{1} 4 - 4 x^{2} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{1} 4 d x - \int_{- 1}^{1} 4 x^{2} d x

\int_{- 1}^{1} 4 d x = 8

\int_{- 1}^{1} 4 x^{2} d x = \frac{8}{3}

= 8 - \frac{8}{3}

Simplify

8 - \frac{8}{3} : \frac{16}{3}

= \frac{16}{3}

Popular Examples

derivative of (4-2x-x^2/(x^2-6))

\frac{d}{d x} (\frac{4 - 2 x - x ^{2}}{x ^{2} - 6})

xv'+v=((1+2v))/(1-v)

x v^{'} + v = \frac{( 1 + 2 v )}{1 - v}

derivative of x^4ln(x)derivative of

x^{4} ln (x)

4y^{''}-8y^'+7y=0

4 y^{^{''}} - 8 y^{^{'}} + 7 y = 0

y^{''}+64y=sec^2(8x)

y^{^{''}} + 64 y = sec^{2} (8 x)

Frequently Asked Questions (FAQ)

What is the integral from-1 to 1 of 4-4x^2 ?
The integral from-1 to 1 of 4-4x^2 is 16/3