We've updated our
Privacy Policy effective December 15.
Please read our updated Privacy Policy and tap
Graph
Hide Plot »
Frequently Asked Questions (FAQ)
What is the solution for 4y^{''}-8y^'+7y=0 ?
- The solution for 4y^{''}-8y^'+7y=0 is y=e^t(c_{1}cos((sqrt(3)t)/2)+c_{2}sin((sqrt(3)t)/2))