y^{''}+64y=sec^2(8x)

解答

y^{^{''}} + 64 y = sec^{2} (8 x)

y = c_{1} cos (8 x) + c_{2} sin (8 x) + \frac{- 1 + ln ( tan ( 8 x ) + sec ( 8 x ) ) sin ( 8 x )}{64}

求解步骤

y^{''} (x) + 64 y = sec^{2} (8 x)

求解线性方程:

y = c_{1} cos (8 x) + c_{2} sin (8 x) + \frac{- 1 + ln ( tan ( 8 x ) + sec ( 8 x ) ) sin ( 8 x )}{64}

y = c_{1} cos (8 x) + c_{2} sin (8 x) + \frac{- 1 + ln ( tan ( 8 x ) + sec ( 8 x ) ) sin ( 8 x )}{64}

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