What is the derivative of x^4ln(x) ?

The derivative of x^4ln(x) is 4x^3ln(x)+x^3

What is the first derivative of x^4ln(x) ?

The first derivative of x^4ln(x) is 4x^3ln(x)+x^3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

x^{4} ln (x)

4 x^{3} ln (x) + x^{3}

Solution steps

\frac{d}{d x} (x^{4} ln (x))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x^{4}, g = ln (x)

= \frac{d}{d x} (x^{4}) ln (x) + \frac{d}{d x} (ln (x)) x^{4}

\frac{d}{d x} (x^{4}) = 4 x^{3}

\frac{d}{d x} (ln (x)) = \frac{1}{x}

= 4 x^{3} ln (x) + \frac{1}{x} x^{4}

\frac{1}{x} x^{4} = x^{3}

= 4 x^{3} ln (x) + x^{3}

4 y^{^{''}} - 8 y^{^{'}} + 7 y = 0

y^{^{''}} + 64 y = sec^{2} (8 x)

\int cos (4 x + 1) d x

\int tan^{3} (1) d x

\frac{d}{d x} (a \cdot b^{x})

What is the derivative of x^4ln(x) ?
The derivative of x^4ln(x) is 4x^3ln(x)+x^3
What is the first derivative of x^4ln(x) ?
The first derivative of x^4ln(x) is 4x^3ln(x)+x^3