What is area-1/2 x^3+2x^2+15/2 x-9,[1,6] ?

The answer to area-1/2 x^3+2x^2+15/2 x-9,[1,6] is 1625/24

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area-1/2 x^3+2x^2+15/2 x-9,[1,6]

area

- \frac{1}{2} x^{3} + 2 x^{2} + \frac{15}{2} x - 9, [1, 6]

\frac{1625}{24}

Solution steps

Apply the area formula:

\int_{1}^{6} - \frac{1}{2} x^{3} + 2 x^{2} + \frac{15}{2} x - 9 d x

Solve

\int_{1}^{6} - \frac{1}{2} x^{3} + 2 x^{2} + \frac{15}{2} x - 9 d x : \frac{1625}{24}

The area is:

= \frac{1625}{24}

\int_{- 1}^{1} 4 - 4 x^{2} d x

\frac{d}{d x} (\frac{4 - 2 x - x ^{2}}{x ^{2} - 6})

x v^{'} + v = \frac{( 1 + 2 v )}{1 - v}

x^{4} ln (x)

4 y^{^{''}} - 8 y^{^{'}} + 7 y = 0

What is area-1/2 x^3+2x^2+15/2 x-9,[1,6] ?
The answer to area-1/2 x^3+2x^2+15/2 x-9,[1,6] is 1625/24