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受欢迎的三角函数 >

1/((sec(a)-tan(a)))=sec(a)+tan(x)

解答

\frac{1}{( sec ( a ) - tan ( a ) )} = sec (a) + tan (x)

解答

x = arctan (\frac{1}{sec ( a ) - tan ( a )} - sec (a)) + πn

求解步骤

\frac{1}{( sec ( a ) - tan ( a ) )} = sec (a) + tan (x)

交换两边

sec (a) + tan (x) = \frac{1}{sec ( a ) - tan ( a )}

将

sec (a)

到右边

sec (a) + tan (x) = \frac{1}{sec ( a ) - tan ( a )}

两边减去

sec (a)

sec (a) + tan (x) - sec (a) = \frac{1}{sec ( a ) - tan ( a )} - sec (a)

化简

tan (x) = \frac{1}{sec ( a ) - tan ( a )} - sec (a)

tan (x) = \frac{1}{sec ( a ) - tan ( a )} - sec (a)

使用反三角函数性质

tan (x) = \frac{1}{sec ( a ) - tan ( a )} - sec (a)

tan (x) = \frac{1}{sec ( a ) - tan ( a )} - sec (a)

的通解

tan (x) = a \Rightarrow x = arctan (a) + πn

x = arctan (\frac{1}{sec ( a ) - tan ( a )} - sec (a)) + πn

x = arctan (\frac{1}{sec ( a ) - tan ( a )} - sec (a)) + πn

作图

流行的例子

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