solvefor x,t^2=2sec(x)

Lösung

löse nach

x, t^{2} = 2 sec (x)

x = arcsec (\frac{t ^{2}}{2}) + 2 πn, x = - arcsec (\frac{t ^{2}}{2}) + 2 πn

Schritte zur Lösung

t^{2} = 2 sec (x)

Tausche die Seiten

2 sec (x) = t^{2}

Teile beide Seiten durch

2

2 sec (x) = t^{2}

Teile beide Seiten durch

2

\frac{2 sec ( x )}{2} = \frac{t ^{2}}{2}

Vereinfache

sec (x) = \frac{t ^{2}}{2}

sec (x) = \frac{t ^{2}}{2}

Wende die Eigenschaften der Trigonometrie an

sec (x) = \frac{t ^{2}}{2}

Allgemeine Lösung für

sec (x) = \frac{t ^{2}}{2}

sec (x) = a \Rightarrow x = arcsec (a) + 2 πn, x = - arcsec (a) + 2 πn

x = arcsec (\frac{t ^{2}}{2}) + 2 πn, x = - arcsec (\frac{t ^{2}}{2}) + 2 πn

x = arcsec (\frac{t ^{2}}{2}) + 2 πn, x = - arcsec (\frac{t ^{2}}{2}) + 2 πn

(8 cos (x) - 4) (sin (x)) = 0, 0 \leq x < 2 π

sin (x) = 3511

\frac{10}{sin ( 3 0 ^{\circ} )} = \frac{3}{sin ( b )}

tan (\frac{θ}{2} - \frac{π}{6}) = - 1, 0 \leq θ < 2 π

arctan (x + 2) - arctan (x + 1) = \frac{π}{4}