What is the general solution for tan(b)=sqrt(3) ?

The general solution for tan(b)=sqrt(3) is b= pi/3+pin

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tan(b)=sqrt(3)

tan (b) = 3

b = \frac{π}{3} + πn

Degrees

b = 6 0^{\circ} + 18 0^{\circ} n

Solution steps

tan (b) = 3

General solutions for

tan (b) = 3

tan (x)

periodicity table with

πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} tan (x) 0 \frac{3}{3} 13 \pm \infty - 3 - 1 - \frac{3}{3}

b = \frac{π}{3} + πn

b = \frac{π}{3} + πn

sin (x) = \frac{12}{16}

\frac{1}{tan ( x )} - 2 tan (x) = - \frac{1}{4}

tan (a) = \frac{3}{2}

cos (x + \frac{π}{6}) = - 1

tan (4 x + 20) \cdot cot (x + 5 0^{\circ}) = 1

What is the general solution for tan(b)=sqrt(3) ?
The general solution for tan(b)=sqrt(3) is b= pi/3+pin