cos(θ)= 2/5 ,cot(θ)<0

Lösung

cos (θ) = \frac{2}{5}, cot (θ) < 0

Keine L \overset{o}{¨} sung f \overset{u}{¨} r θ \in R

Schritte zur Lösung

cos (θ) = \frac{2}{5}, cot (θ) < 0

Wende die Eigenschaften der Trigonometrie an

cos (θ) = \frac{2}{5}

Allgemeine Lösung für

cos (θ) = \frac{2}{5}

cos (x) = a \Rightarrow x = arccos (a) + 2 πn, x = 2 π - arccos (a) + 2 πn

θ = arccos (\frac{2}{5}) + 2 πn, θ = 2 π - arccos (\frac{2}{5}) + 2 πn

θ = arccos (\frac{2}{5}) + 2 πn, θ = 2 π - arccos (\frac{2}{5}) + 2 πn

Lösungen für den Bereich

cot (θ) < 0

Keine L \overset{o}{¨} sung f \overset{u}{¨} r θ \in R

so l v e f or b, s (t) = tan (b t^{2})

tan (x) = \frac{80}{90}

4 cos^{2} (x) - 11 cos (x) + 6 = 0

tanh (x) = 0.99

3 cos (3 0^{\circ}) + 4 cos (y) = 3