beweisen 1+tan^2(45)=sec^2(45)

Lösung

beweisen

1 + tan^{2} (4 5^{\circ}) = sec^{2} (4 5^{\circ})

Wahr

Schritte zur Lösung

1 + tan^{2} (4 5^{\circ}) = sec^{2} (4 5^{\circ})

Verwende die Pythagoreische Identität:

tan^{2} (x) + 1 = sec^{2} (x)

\Rightarrow Wahr

p ro v e \frac{cot ( x )}{cos ( x )} = csc (x)

p ro v e \frac{sin ( x ) cos ( x )}{tan ( x )} = cos^{2} (x)

p ro v e 2 sin^{2} (2 t) + cos (4 t) = 1

p ro v e \frac{cos ( θ ) + cos ( 3 θ )}{2 cos ( 2 θ )} = cos (θ)

p ro v e sin (27 0^{\circ} + x) = - cos (x)