What is the general solution for cos(x)=1,0<= x<2pi ?

The general solution for cos(x)=1,0<= x<2pi is x=0

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cos(x)=1,0<= x<2pi

cos (x) = 1, 0 \leq x < 2 π

x = 0

Degrees

x = 0^{\circ}

Solution steps

cos (x) = 1, 0 \leq x < 2 π

General solutions for

cos (x) = 1

cos (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

x = 0 + 2 πn

x = 0 + 2 πn

Solve

x = 0 + 2 πn : x = 2 πn

x = 0 + 2 πn

0 + 2 πn = 2 πn

x = 2 πn

x = 2 πn

Solutions for the range

0 \leq x < 2 π

x = 0

sin (t) = \frac{1}{3}

5 csc (x) - 3 = 2

2 cos^{2} (x) + 2 = 4

sin (z) = 3

3 sin (\frac{θ}{2}) + sin (θ) = 0

What is the general solution for cos(x)=1,0<= x<2pi ?
The general solution for cos(x)=1,0<= x<2pi is x=0