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受欢迎的初等代数 >

10^9-1\div 999

解答

1 0^{9} - 1 \div 999

解答

\frac{998999999999}{999}

+1

十进制

999999999.99899 \dots

求解步骤

1 0^{9} - 1 \div 999

遵循 PEMDAS 运算顺序

计算幂值

1 0^{9} : 1000000000

1 0^{9}

1 0^{9} = 1000000000

= 1000000000

= 1000000000 - 1 \div 999

乘除（左右）

1 \div 999 : \frac{1}{999}

1 \div 999

1 \div 999 = \frac{1}{999}

= \frac{1}{999}

= 1000000000 - \frac{1}{999}

加减（左右）

1000000000 - \frac{1}{999} : \frac{998999999999}{999}

1000000000 - \frac{1}{999}

1000000000 - \frac{1}{999} = \frac{998999999999}{999}

1000000000 - \frac{1}{999}

将项转换为分式:

1000000000 = \frac{1000000000 \cdot 999}{999}

= \frac{1000000000 \cdot 999}{999} - \frac{1}{999}

因为分母相等，所以合并分式:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{1000000000 \cdot 999 - 1}{999}

1000000000 \cdot 999 - 1 = 998999999999

1000000000 \cdot 999 - 1

数字相乘:

1000000000 \cdot 999 = 999000000000

= 999000000000 - 1

数字相减:

999000000000 - 1 = 998999999999

= 998999999999

= \frac{998999999999}{999}

= \frac{998999999999}{999}

= \frac{998999999999}{999}

流行的例子

(-3)*[(-2)+(-5)]

(- 3) \cdot [(- 2) + (- 5)]

(4^2(22-18))/(3(-7)-(-4)(-2))

\frac{4 ^{2} ( 22 - 18 )}{3 ( - 7 ) - ( - 4 ) ( - 2 )}

1/12 × 5× 8^3

\frac{1}{12} \times 5 \times 8^{3}

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4^3\div 2-2^3× 6+8(-1)^{10}

4^{3} \div 2 - 2^{3} \times 6 + 8 (- 1)^{10}