What is (4-3\times 2^3)^2 ?

The solution to (4-3\times 2^3)^2 is 400

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(4-3\times 2^3)^2

(4 - 3 \cdot 2^{3})^{2}

400

Solution steps

(4 - 3 \cdot 2^{3})^{2}

Follow the PEMDAS order of operations

Calculate within parentheses

(4 - 3 \cdot 2^{3}) : - 20

4 - 3 \cdot 2^{3}

Calculate exponents

2^{3} : 8

2^{3}

2^{3} = 8

= 8

= 4 - 3 \cdot 8

Multiply and divide (left to right)

3 \cdot 8 : 24

3 \cdot 8

3 \cdot 8 = 24

= 24

= 4 - 24

Add and subtract (left to right)

4 - 24 : - 20

4 - 24

4 - 24 = - 20

= - 20

= - 20

= (- 20)^{2}

Calculate exponents

(- 20)^{2} : 400

(- 20)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 20)^{2} = 2 0^{2} = 400

= 400

= 400

0^{3} + 1

(3^{2} \times 4^{2}) \times (- 1)^{5}

(- 12) - (- 3) + (+ 5)

3^{2} - 2 (3) (4) + 4^{2}

2 (2)^{3} + 3