What is 3^2-2(3)(4)+4^2 ?

The solution to 3^2-2(3)(4)+4^2 is 1

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3^2-2(3)(4)+4^2

3^{2} - 2 (3) (4) + 4^{2}

1

Solution steps

3^{2} - 2 (3) (4) + 4^{2}

Follow the PEMDAS order of operations

Calculate exponents

3^{2} : 9

3^{2}

3^{2} = 9

= 9

= 9 - 2 (3) (4) + 4^{2}

Calculate exponents

4^{2} : 16

4^{2}

4^{2} = 16

= 16

= 9 - 2 (3) (4) + 16

Multiply and divide (left to right)

2 (3) (4) : 24

2 (3) (4)

2 (3) = 6

2 (3)

Apply rule:

(a) = a

(3) = 3

= 2 \cdot 3

Multiply the numbers:

2 \cdot 3 = 6

= 6

= 6 (4)

6 (4) = 24

6 (4)

Apply rule:

(a) = a

(4) = 4

= 6 \cdot 4

Multiply the numbers:

6 \cdot 4 = 24

= 24

= 24

= 9 - 24 + 16

Add and subtract (left to right)

9 - 24 + 16 : 1

9 - 24 + 16

9 - 24 = - 15

= - 15 + 16

- 15 + 16 = 1

= 1

= 1

2 (2)^{3} + 3

2 (2)^{3} + 4

7 \cdot 1 0^{2}

5 (2^{2} - 5) + 4 \times 3^{2} - 15 - 2

4^{5} + 2^{5} + 3^{5}