What is 3\times (-2)^2+5\times (-2)-2 ?

The solution to 3\times (-2)^2+5\times (-2)-2 is 0

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3\times (-2)^2+5\times (-2)-2

3 \cdot (- 2)^{2} + 5 \cdot (- 2) - 2

0

Solution steps

3 (- 2)^{2} + 5 (- 2) - 2

Follow the PEMDAS order of operations

Calculate exponents

(- 2)^{2} : 4

(- 2)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 2)^{2} = 2^{2} = 4

= 4

= 3 \cdot 4 + 5 (- 2) - 2

Multiply and divide (left to right)

3 \cdot 4 : 12

3 \cdot 4

3 \cdot 4 = 12

= 12

= 12 + 5 (- 2) - 2

Multiply and divide (left to right)

5 (- 2) : - 10

5 (- 2)

Apply rule

a \cdot (- b) = - a \cdot b

5 (- 2) = - 5 \cdot 2 = - 10

= - 10

= 12 - 10 - 2

Add and subtract (left to right)

12 - 10 - 2 : 0

12 - 10 - 2

12 - 10 = 2

= 2 - 2

2 - 2 = 0

= 0

= 0

1^{2} - 1^{2}

(\frac{10}{7}) (\frac{5}{4} + \frac{4}{5})

(+ 8 - 3 - 2 - 1)^{3} (+ 12 - 3 - 4)^{2}

(3)^{3} - 2

(- 2) - (- \frac{3}{4}) \div (- 3)

What is 3\times (-2)^2+5\times (-2)-2 ?
The solution to 3\times (-2)^2+5\times (-2)-2 is 0