What is (-2)-(-3/4)\div (-3) ?

The solution to (-2)-(-3/4)\div (-3) is -9/4

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(-2)-(-3/4)\div (-3)

(- 2) - (- \frac{3}{4}) \div (- 3)

- \frac{9}{4}

Solution steps

(- 2) - (- \frac{3}{4}) \div (- 3)

Follow the PEMDAS order of operations

Multiply and divide (left to right)

(- \frac{3}{4}) \div (- 3) : \frac{1}{4}

(- \frac{3}{4}) \div (- 3)

Apply rule

(- a) \div (- b) = a \div b

(- \frac{3}{4}) \div (- 3) = \frac{3}{4} \div 3

Convert element to fraction:

3 = \frac{3}{1}

= \frac{3}{4} \div \frac{3}{1}

Apply the fraction rule:

\frac{a}{b} \div \frac{c}{d} = \frac{a}{b} \times \frac{d}{c}

= \frac{3}{4} \cdot \frac{1}{3}

Cross-cancel:

3

= \frac{1}{4}

= (- 2) - \frac{1}{4}

Add and subtract (left to right)

(- 2) - \frac{1}{4} : - \frac{9}{4}

(- 2) - \frac{1}{4}

(- 2) - \frac{1}{4} = - \frac{9}{4}

= - \frac{9}{4}

= - \frac{9}{4}

(9348 \div 2) \div 2

\frac{2 ( - 3 ) ^{2} - 1}{( - 3 ) ^{2}}

2 (3)^{3} - (8 + 9 \cdot 2)

(4 - \frac{1}{4}) \times 1

- (4 - 15 - (7 - (3 - 2 - 6) - 8) - (- 3 - (7 - 5)))