What is 3^2-4(3)(-10) ?

The solution to 3^2-4(3)(-10) is 129

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3^2-4(3)(-10)

3^{2} - 4 (3) (- 10)

129

Solution steps

3^{2} - 4 (3) (- 10)

Follow the PEMDAS order of operations

Calculate exponents

3^{2} : 9

3^{2}

3^{2} = 9

= 9

= 9 - 4 (3) (- 10)

Multiply and divide (left to right)

4 (3) (- 10) : - 120

4 (3) (- 10)

4 (3) = 12

4 (3)

Apply rule:

(a) = a

(3) = 3

= 4 \cdot 3

Multiply the numbers:

4 \cdot 3 = 12

= 12

= 12 (- 10)

Apply rule

a \cdot (- b) = - a \cdot b

12 (- 10) = - 12 \cdot 10 = - 120

= - 120

= 9 - (- 120)

Add and subtract (left to right)

9 - (- 120) : 129

9 - (- 120)

Apply rule

- (- a) = + a

- (- 120) = + 120

= 9 + 120

9 + 120 = 129

= 129

= 129

12 (- 3)^{2}

4 \times 17 - 3

- 4 \times 1 \div 1000000

20 \div (3 + 2)

4 (\frac{9}{4} + \frac{5}{7} - 7)