What is (1-5/7)*(2-3/5) ?

The solution to (1-5/7)*(2-3/5) is 2/5

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(1-5/7)*(2-3/5)

(1 - \frac{5}{7}) \cdot (2 - \frac{3}{5})

\frac{2}{5}

Solution steps

(1 - \frac{5}{7}) (2 - \frac{3}{5})

Follow the PEMDAS order of operations

Calculate within parentheses

(1 - \frac{5}{7}) : \frac{2}{7}

1 - \frac{5}{7}

1 - \frac{5}{7} = \frac{2}{7}

1 - \frac{5}{7}

Convert element to fraction:

1 = \frac{1 \cdot 7}{7}

= \frac{1 \cdot 7}{7} - \frac{5}{7}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{1 \cdot 7 - 5}{7}

1 \cdot 7 - 5 = 2

1 \cdot 7 - 5

Multiply the numbers:

1 \cdot 7 = 7

= 7 - 5

Subtract the numbers:

7 - 5 = 2

= 2

= \frac{2}{7}

= \frac{2}{7}

= \frac{2}{7} (2 - \frac{3}{5})

Calculate within parentheses

(2 - \frac{3}{5}) : \frac{7}{5}

2 - \frac{3}{5}

2 - \frac{3}{5} = \frac{7}{5}

2 - \frac{3}{5}

Convert element to fraction:

2 = \frac{2 \cdot 5}{5}

= \frac{2 \cdot 5}{5} - \frac{3}{5}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{2 \cdot 5 - 3}{5}

2 \cdot 5 - 3 = 7

2 \cdot 5 - 3

Multiply the numbers:

2 \cdot 5 = 10

= 10 - 3

Subtract the numbers:

10 - 3 = 7

= 7

= \frac{7}{5}

= \frac{7}{5}

= \frac{2}{7} \cdot \frac{7}{5}

Multiply and divide (left to right)

\frac{2}{7} \cdot \frac{7}{5} : \frac{2}{5}

\frac{2}{7} \cdot \frac{7}{5}

\frac{2}{7} \cdot \frac{7}{5} = \frac{2}{5}

= \frac{2}{5}

= \frac{2}{5}

7/10 \times 5/8 \times 96

(- 3)^{2} - (- 3) - 12

\frac{3}{4} (2) + 2

3^{1} - 2^{2} + 1^{3}

16 - 10 \div 5 + 13