What is -180(1-5/50) ?

The solution to -180(1-5/50) is -162

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-180(1-5/50)

- 180 (1 - \frac{5}{50})

- 162

Solution steps

- 180 (1 - \frac{5}{50})

\frac{5}{50} = \frac{1}{10}

Cancel the common factor:

5

\frac{1}{10}

= - 180 (1 - \frac{1}{10})

Follow the PEMDAS order of operations

Calculate within parentheses

(1 - \frac{1}{10}) : \frac{9}{10}

1 - \frac{1}{10}

1 - \frac{1}{10} = \frac{9}{10}

1 - \frac{1}{10}

Convert element to fraction:

1 = \frac{1 \cdot 10}{10}

= \frac{1 \cdot 10}{10} - \frac{1}{10}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{1 \cdot 10 - 1}{10}

1 \cdot 10 - 1 = 9

1 \cdot 10 - 1

Multiply the numbers:

1 \cdot 10 = 10

= 10 - 1

Subtract the numbers:

10 - 1 = 9

= 9

= \frac{9}{10}

= \frac{9}{10}

= - 180 \cdot \frac{9}{10}

Multiply and divide (left to right)

- 180 \cdot \frac{9}{10} : - 162

- 180 \cdot \frac{9}{10}

Convert element to fraction:

180 = \frac{180}{1}

= - \frac{180}{1} \cdot \frac{9}{10}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

\frac{180}{1} \cdot \frac{9}{10} = \frac{180 \cdot 9}{1 \cdot 10}

= - \frac{180 \cdot 9}{1 \cdot 10}

Cancel

\frac{180 \cdot 9}{1 \cdot 10} : 162

\frac{180 \cdot 9}{1 \cdot 10}

Multiply the numbers:

1 \cdot 10 = 10

= \frac{180 \cdot 9}{10}

Divide the numbers:

\frac{180}{10} = 18

= 18 \cdot 9

Multiply the numbers:

18 \cdot 9 = 162

= 162

= - 162

= - 162

3^{2} - 4 (3) (- 10)

12 (- 3)^{2}

4 \times 17 - 3

- 4 \times 1 \div 1000000

20 \div (3 + 2)