(x+1)^2=-12(y-6)

Lösung

(x + 1)^{2} = - 12 (y - 6)

(h, k) = (- 1, 6), p = - 3

Schritte zur Lösung

(x + 1)^{2} = - 12 (y - 6)

Rewrite

(x + 1)^{2} = - 12 (y - 6)

in the standard form:

4 (- 3) (y - 6) = (x - (- 1))^{2}

Therefore parabola properties are:

(h, k) = (- 1, 6), p = - 3

x^{2} + (y - 3) 2 = 16

x + (y - 1)^{2} = 1

x - 2 y^{2} - 12 y - 13 = 0

2 x^{2} - 2 y = 0

y = 2 x^{2} + 16 x + 29