x-2y^2-12y-13=0

Lösung

x - 2 y^{2} - 12 y - 13 = 0

(h, k) = (- 5, - 3), p = \frac{1}{8}

Schritte zur Lösung

x - 2 y^{2} - 12 y - 13 = 0

Rewrite

x - 2 y^{2} - 12 y - 13 = 0

in the standard form

4 \cdot \frac{1}{8} (x - (- 5)) = (y - (- 3))^{2}

Therefore parabola properties are:

(h, k) = (- 5, - 3), p = \frac{1}{8}

2 x^{2} - 2 y = 0

y = 2 x^{2} + 16 x + 29

x^{2} + 5 x = - y + 6

x^{2} - 16 x - 8 y + 80 = 0

x + 2 = y^{2}