What is y^2+5y+25/4 =-5x+45/2 ?

The solution to y^2+5y+25/4 =-5x+45/2 is Parabola with (h,k)=(9/2 ,-5/2),p=-5/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^2+5y+25/4 =-5x+45/2

y^{2} + 5 y + \frac{25}{4} = - 5 x + \frac{45}{2}

(h, k) = (\frac{9}{2}, - \frac{5}{2}), p = - \frac{5}{4}

Solution steps

y^{2} + 5 y + \frac{25}{4} = - 5 x + \frac{45}{2}

Rewrite

y^{2} + 5 y + \frac{25}{4} = - 5 x + \frac{45}{2}

in the standard form

4 (- \frac{5}{4}) (x - \frac{9}{2}) = (y - (- \frac{5}{2}))^{2}

Therefore parabola properties are:

(h, k) = (\frac{9}{2}, - \frac{5}{2}), p = - \frac{5}{4}

(3 x^{2}) - 12 x - 8 y - 4 = 0

4 x^{2} - 3 y = 0

2 x^{2} - 8 + b y (x) + 10 = 0

2 x - 3 y^{2} = 18

- 4 x + y^{2} - 8 = 0

What is y^2+5y+25/4 =-5x+45/2 ?
The solution to y^2+5y+25/4 =-5x+45/2 is Parabola with (h,k)=(9/2 ,-5/2),p=-5/4