-4x+y^2-8=0

Lösung

- 4 x + y^{2} - 8 = 0

(h, k) = (- 2, 0), p = 1

Schritte zur Lösung

- 4 x + y^{2} - 8 = 0

Rewrite

- 4 x + y^{2} - 8 = 0

in the standard form:

4 \cdot 1 \cdot (x - (- 2)) = (y - 0)^{2}

Therefore parabola properties are:

(h, k) = (- 2, 0), p = 1

(x - 4)^{2} = - 12 (y - 3)

x^{2} + 6 x - 4 y + 5 = 0

4 y^{2} - 12 x - 6 y + 19 = 0

y^{2} = 4 x + 1

x^{2} = 100 (y - 1)