What is 4y^2-12x-6y+19=0 ?

The solution to 4y^2-12x-6y+19=0 is Parabola with (h,k)=(67/48 , 3/4),p= 3/4

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4y^2-12x-6y+19=0

4 y^{2} - 12 x - 6 y + 19 = 0

(h, k) = (\frac{67}{48}, \frac{3}{4}), p = \frac{3}{4}

Solution steps

4 y^{2} - 12 x - 6 y + 19 = 0

Rewrite

4 y^{2} - 12 x - 6 y + 19 = 0

in the standard form

4 \cdot \frac{3}{4} (x - \frac{67}{48}) = (y - \frac{3}{4})^{2}

Therefore parabola properties are:

(h, k) = (\frac{67}{48}, \frac{3}{4}), p = \frac{3}{4}

y^{2} = 4 x + 1

x^{2} = 100 (y - 1)

y - 4 x^{2} = 0

(x + 1)^{2} = - 12 (y - 6)

x^{2} + (y - 3) 2 = 16

What is 4y^2-12x-6y+19=0 ?
The solution to 4y^2-12x-6y+19=0 is Parabola with (h,k)=(67/48 , 3/4),p= 3/4