4x^2-3y=0

Lösung

4 x^{2} - 3 y = 0

(h, k) = (0, 0), p = \frac{3}{16}

Schritte zur Lösung

4 x^{2} - 3 y = 0

Rewrite

4 x^{2} - 3 y = 0

in the standard form:

4 \cdot \frac{3}{16} (y - 0) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 0), p = \frac{3}{16}

2 x^{2} - 8 + b y (x) + 10 = 0

2 x - 3 y^{2} = 18

- 4 x + y^{2} - 8 = 0

(x - 4)^{2} = - 12 (y - 3)

x^{2} + 6 x - 4 y + 5 = 0