What is the center ((x+5)^2)/(1/9)-((y-3)^2)/(1/4)=1 ?

The center ((x+5)^2)/(1/9)-((y-3)^2)/(1/4)=1 is (-5,3)

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center ((x+5)^2)/(1/9)-((y-3)^2)/(1/4)=1

center

\frac{( x + 5 ) ^{2}}{\frac{1}{9}} - \frac{( y - 3 ) ^{2}}{\frac{1}{4}} = 1

(- 5, 3)

Solution steps

\frac{( x + 5 ) ^{2}}{\frac{1}{9}} - \frac{( y - 3 ) ^{2}}{\frac{1}{4}} = 1

Rewrite

\frac{( x + 5 ) ^{2}}{\frac{1}{9}} - \frac{( y - 3 ) ^{2}}{\frac{1}{4}} = 1

in the form of a standard hyperbola equation

\frac{( x - ( - 5 ) ) ^{2}}{( \frac{1}{3} ) ^{2}} - \frac{( y - 3 ) ^{2}}{( \frac{1}{2} ) ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (- 5, 3), a = \frac{1}{3}, b = \frac{1}{2}

And the center is:

(- 5, 3)

\frac{( x + 2 ) ^{2}}{16} - \frac{( y - 1 ) ^{2}}{9} = 1

\frac{x ^{2}}{289} - \frac{y ^{2}}{144} = 1

\frac{y ^{2}}{4} - \frac{x ^{2}}{1} = 1

121 - 32 x - 8 x^{2} - 90 y + 9 y^{2} = 0

y^{2} - 4 x^{2} = 36

What is the center ((x+5)^2)/(1/9)-((y-3)^2)/(1/4)=1 ?
The center ((x+5)^2)/(1/9)-((y-3)^2)/(1/4)=1 is (-5,3)