What is the center (y^2)/4-(x^2)/1 =1 ?

The center (y^2)/4-(x^2)/1 =1 is (0,0)

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center (y^2)/4-(x^2)/1 =1

center

\frac{y ^{2}}{4} - \frac{x ^{2}}{1} = 1

(0, 0)

Solution steps

\frac{y ^{2}}{4} - \frac{x ^{2}}{1} = 1

Rewrite

\frac{y ^{2}}{4} - \frac{x ^{2}}{1} = 1

in the form of a standard hyperbola equation

\frac{( y - 0 ) ^{2}}{2 ^{2}} - \frac{( x - 0 ) ^{2}}{1 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 2, b = 1

And the center is:

(0, 0)

121 - 32 x - 8 x^{2} - 90 y + 9 y^{2} = 0

y^{2} - 4 x^{2} = 36

10 x^{2} - 6 y^{2} - 20 x - 24 y + 46 = 0

- 4 x^{2} + 24 x + 16 y^{2} - 128 y + 156 = 0

\frac{( x - 1 ) ^{2}}{9} - \frac{( y + 6 ) ^{2}}{4} = 1