What is the center y^2-4x^2=36 ?

The center y^2-4x^2=36 is (0,0)

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center y^2-4x^2=36

center

y^{2} - 4 x^{2} = 36

(0, 0)

Solution steps

y^{2} - 4 x^{2} = 36

Rewrite

y^{2} - 4 x^{2} = 36

in the form of a standard hyperbola equation

\frac{( y - 0 ) ^{2}}{6 ^{2}} - \frac{( x - 0 ) ^{2}}{3 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 6, b = 3

And the center is:

(0, 0)

10 x^{2} - 6 y^{2} - 20 x - 24 y + 46 = 0

- 4 x^{2} + 24 x + 16 y^{2} - 128 y + 156 = 0

\frac{( x - 1 ) ^{2}}{9} - \frac{( y + 6 ) ^{2}}{4} = 1

25 x^{2} - 4 y^{2} - 100 x - 16 y - 16 = 0

9 x^{2} - 16 y^{2} - 36 x + 96 y + 252 = 0