What is the center ((y-4)^2)/(81)-((x+5)^2)/(36)=1 ?

The center ((y-4)^2)/(81)-((x+5)^2)/(36)=1 is (-5,4)

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center ((y-4)^2)/(81)-((x+5)^2)/(36)=1

center

\frac{( y - 4 ) ^{2}}{81} - \frac{( x + 5 ) ^{2}}{36} = 1

(- 5, 4)

Solution steps

\frac{( y - 4 ) ^{2}}{81} - \frac{( x + 5 ) ^{2}}{36} = 1

Rewrite

\frac{( y - 4 ) ^{2}}{81} - \frac{( x + 5 ) ^{2}}{36} = 1

in the form of a standard hyperbola equation

\frac{( y - 4 ) ^{2}}{9 ^{2}} - \frac{( x - ( - 5 ) ) ^{2}}{6 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (- 5, 4), a = 9, b = 6

And the center is:

(- 5, 4)

3 x^{2} - y^{2} - 12 x + 4 y + 2 = 0

\frac{x ^{2}}{49} - \frac{y ^{2}}{36} = 1

9 x^{2} - 4 y^{2} + 54 x - 8 y + 78 = 0

\frac{x ^{2}}{4} - \frac{y ^{2}}{12} = 1

\frac{( x - 2 ) ^{2}}{4} - \frac{y ^{2}}{9} = 1

What is the center ((y-4)^2)/(81)-((x+5)^2)/(36)=1 ?
The center ((y-4)^2)/(81)-((x+5)^2)/(36)=1 is (-5,4)