What is the center ((x-2)^2)/4-(y^2)/9 =1 ?

The center ((x-2)^2)/4-(y^2)/9 =1 is (2,0)

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center ((x-2)^2)/4-(y^2)/9 =1

center

\frac{( x - 2 ) ^{2}}{4} - \frac{y ^{2}}{9} = 1

(2, 0)

Solution steps

\frac{( x - 2 ) ^{2}}{4} - \frac{y ^{2}}{9} = 1

Rewrite

\frac{( x - 2 ) ^{2}}{4} - \frac{y ^{2}}{9} = 1

in the form of a standard hyperbola equation

\frac{( x - 2 ) ^{2}}{2 ^{2}} - \frac{( y - 0 ) ^{2}}{3 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (2, 0), a = 2, b = 3

And the center is:

(2, 0)

- 321 + 108 x - 9 x^{2} + 8 y + 4 y^{2} = 0

\frac{( y - 5 ) ^{2}}{81} - \frac{( x + 8 ) ^{2}}{9} = 1

\frac{x ^{2}}{64} - \frac{y ^{2}}{36} = 1

3 (x + 2)^{2} - 6 (y - 6)^{2} - 18 = 0

x^{2} - 6 x - 6 = y^{2} + 6 y + 6

What is the center ((x-2)^2)/4-(y^2)/9 =1 ?
The center ((x-2)^2)/4-(y^2)/9 =1 is (2,0)