What is the center (x^2)/(60)-(y^2)/(40)=1 ?

The center (x^2)/(60)-(y^2)/(40)=1 is (0,0)

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center (x^2)/(60)-(y^2)/(40)=1

center

\frac{x ^{2}}{60} - \frac{y ^{2}}{40} = 1

(0, 0)

Solution steps

\frac{x ^{2}}{60} - \frac{y ^{2}}{40} = 1

Rewrite

\frac{x ^{2}}{60} - \frac{y ^{2}}{40} = 1

in the form of a standard hyperbola equation

\frac{( x - 0 ) ^{2}}{( 2 15 ) ^{2}} - \frac{( y - 0 ) ^{2}}{( 2 10 ) ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 215, b = 210

And the center is:

(0, 0)

x^{2} - y^{2} - 2 x - 2 y - 1 = 0

\frac{x ^{2}}{36} - \frac{y ^{2}}{4} = 1

4 x^{2} - 25 y^{2} + 100 y = 200

\frac{x ^{2}}{9} - \frac{y ^{2}}{64} = 1

9 x^{2} - 16 y^{2} - 36 x - 96 y - 252 = 0

What is the center (x^2)/(60)-(y^2)/(40)=1 ?
The center (x^2)/(60)-(y^2)/(40)=1 is (0,0)