What is the center (x^2}{36}-\frac{y^2)/4 =1 ?

The center (x^2}{36}-\frac{y^2)/4 =1 is (0,0)

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center (x^2}{36}-\frac{y^2)/4 =1

center

\frac{x ^{2}}{36} - \frac{y ^{2}}{4} = 1

(0, 0)

Solution steps

\frac{x ^{2}}{36} - \frac{y ^{2}}{4} = 1

Rewrite

\frac{x ^{2}}{36} - \frac{y ^{2}}{4} = 1

in the form of a standard hyperbola equation

\frac{( x - 0 ) ^{2}}{6 ^{2}} - \frac{( y - 0 ) ^{2}}{2 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 6, b = 2

And the center is:

(0, 0)

4 x^{2} - 25 y^{2} + 100 y = 200

\frac{x ^{2}}{9} - \frac{y ^{2}}{64} = 1

9 x^{2} - 16 y^{2} - 36 x - 96 y - 252 = 0

4 y^{2} - x^{2} + 24 y + 4 x + 28 = 0

\frac{( y + 6 ) ^{2}}{36} - \frac{( x + 4 ) ^{2}}{48} = 1

What is the center (x^2}{36}-\frac{y^2)/4 =1 ?
The center (x^2}{36}-\frac{y^2)/4 =1 is (0,0)