What is the center 4x^2-25y^2+100y=200 ?

The center 4x^2-25y^2+100y=200 is (0,2)

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center 4x^2-25y^2+100y=200

center

4 x^{2} - 25 y^{2} + 100 y = 200

(0, 2)

Solution steps

4 x^{2} - 25 y^{2} + 100 y = 200

Rewrite

4 x^{2} - 25 y^{2} + 100 y = 200

in the form of a standard hyperbola equation

\frac{( x - 0 ) ^{2}}{5 ^{2}} - \frac{( y - 2 ) ^{2}}{2 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 2), a = 5, b = 2

And the center is:

(0, 2)

\frac{x ^{2}}{9} - \frac{y ^{2}}{64} = 1

9 x^{2} - 16 y^{2} - 36 x - 96 y - 252 = 0

4 y^{2} - x^{2} + 24 y + 4 x + 28 = 0

\frac{( y + 6 ) ^{2}}{36} - \frac{( x + 4 ) ^{2}}{48} = 1

y^{2} - 4 x^{2} - 16 x - 2 y - 19 = 0

What is the center 4x^2-25y^2+100y=200 ?
The center 4x^2-25y^2+100y=200 is (0,2)